If 36, p 9 andą are consecutive terms of an exponential sequence (GP). Find the sum of p and q.
Question
If 36, p 9 andą are consecutive terms of an exponential sequence (GP). Find the sum of p and q.
Solution
In an exponential sequence (also known as a geometric progression), each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.
Given that 36, p, 9, and q are consecutive terms of an exponential sequence, we can set up the following equations based on the property of geometric progression:
- p/36 = 9/p (because the ratio between consecutive terms is constant)
- 9/p = q/9
From equation 1), we can solve for p: p^2 = 36 * 9 p = sqrt(36 * 9) p = 18
Substitute p = 18 into equation 2) to solve for q: 9/18 = q/9 q = 9 * 9 / 18 q = 4.5
Finally, the sum of p and q is 18 + 4.5 = 22.5.
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