While using the direct mapping technique, in a 16 bit system the higher order 5 bits are used for ________Question 22Select one:a.Idb.Blockc.Wordd.Tag

In a system which has 32 registers, the register id is __________ long.Question 2Select one:a.5 bitb.16 bitc.6 bitd.8 bit

Consider a direct mapped cache of size 16 KB with block size128 bytes. The size of main memory is 256 KB. Find thenumber of bits in the tag, line and word/line offset in mainmemory address

Consider a machine with a byte addressable main memory of 216 bytes and block size of 8bytes.Assume that a direct mapped cache consisting of 32 lines is used with this machine.• How is a 16-bit memory address divided into tag, line number, and byte number?• Into what line would bytes with each of the following addresses be stored?000100010001101111000011001101001101000000011101• Suppose the byte with address 0001101000011010 is stored in the cache. Whatare the addresses of the other bytes stored along with it?• How many total bytes of memory can be stored in the cache?

A half byte is known as_____.Select one:a.Datab.Wordc.Bitd.nibble

How to desgin the address format?• We need, block number, word/Byte number, cache line numberblock no. Offset(word/Byte id )• The CPU gives out a 32-bit address Addr. Each byte has an address.• The block size is b, one block b bytes.• Then Addr is in Block Addr/b, and it is the (Addr%b)-th byte in the block.• Modulo is a math operation that finds the remainder, mod, or symbol %.• If the divisor (block size) is in the form of b = 2n, then— A%b is given by the rightmost n-bits of A,— A/b is given by the remaining bits.8 / 28*byte-addressable