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Deandre borrowed money from an online lending company to buy a camper.He took out a personal, amortized loan for $18,000, at an interest rate of 5.2%, with monthly payments for a term of 4 years.For each part, do not round any intermediate computations and round your final answers to the nearest cent.If necessary, refer to the list of financial formulas.(a) Find Deandre's monthly payment.$(b) If Deandre pays the monthly payment each month for the full term, find his total amount to repay the loan.$(c) If Deandre pays the monthly payment each month for the full term, find the total amount of interest he will pay.$

Question

Deandre borrowed money from an online lending company to buy a camper.He took out a personal, amortized loan for 18,000,ataninterestrateof5.218,000, at an interest rate of 5.2%, with monthly payments for a term of 4 years.For each part, do not round any intermediate computations and round your final answers to the nearest cent.If necessary, refer to the list of financial formulas.(a) Find Deandre's monthly payment.(b) If Deandre pays the monthly payment each month for the full term, find his total amount to repay the loan.(c)IfDeandrepaysthemonthlypaymenteachmonthforthefullterm,findthetotalamountofinteresthewillpay.(c) If Deandre pays the monthly payment each month for the full term, find the total amount of interest he will pay.

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Solution 1

(a) To find Deandre's monthly payment, we use the formula for the monthly payment on an amortized loan:

M=Pr(1+r)n(1+r)n1 M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1}

where:

  • M M is the monthly payment
  • P P is the loan principal ($18,000)
  • r r is the monthly interest rate (annual rate divided by 12)
  • n n is the total number of payments (loan term in months)

First, we need to find the monthly interest rate:

r=5.2%12=0.05212=0.0043333 r = \frac{5.2\%}{12} = \frac{0.052}{12} = 0.0043333

Next, we calculate the total number of payments:

n=4 years×12 months/year=48 months n = 4 \text{ years} \times 12 \text{ months/year} = 48 \text{ months}

Now we can plug these values into the formula:

M=180000.0043333(1+0.0043333)48(1+0.0043333)481 M = \frac{18000 \cdot 0.0043333 \cdot (1 + 0.0043333)^{48}}{(1 + 0.0043333)^{48} - 1}

First, calculate (1+0.0043333)48(1 + 0.0043333)^{48}:

(1+0.0043333)481.221386 (1 + 0.0043333)^{48} \approx 1.221386

Now, calculate the numerator:

180000.00433331.22138695.276 18000 \cdot 0.0043333 \cdot 1.221386 \approx 95.276

And the denominator:

1.2213861=0.221386 1.221386 - 1 = 0.221386

Finally, calculate the monthly payment:

M=95.2760.221386430.36 M = \frac{95.276}{0.221386} \approx 430.36

So, Deandre's monthly payment is approximately $430.36.

(b) To find the total amount Deandre will repay over the term of the loan, we multiply the monthly payment by the total number of payments:

Total repayment=M×n=430.36×4820657.28 \text{Total repayment} = M \times n = 430.36 \times 48 \approx 20657.28

So, the total amount to repay the loan is approximately $20,657.28.

(c) To find the total amount of interest Deandre will pay, we subtract the loan principal from the total repayment amount:

Total interest=Total repaymentP=20657.28180002657.28 \text{Total interest} = \text{Total repayment} - P = 20657.28 - 18000 \approx 2657.28

So, the total amount of interest he will pay is approximately $2,657.28.

This problem has been solved

Solution 2

(a) To find Deandre's monthly payment, we use the formula for the monthly payment on an amortized loan:

M=Pr(1+r)n(1+r)n1 M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1}

where:

  • M M is the monthly payment
  • P P is the loan principal ($18,000)
  • r r is the monthly interest rate (annual rate divided by 12)
  • n n is the total number of payments (loan term in months)

First, we need to find the monthly interest rate:

r=5.2%12=0.05212=0.0043333 r = \frac{5.2\%}{12} = \frac{0.052}{12} = 0.0043333

Next, we calculate the total number of payments:

n=4 years×12 months/year=48 months n = 4 \text{ years} \times 12 \text{ months/year} = 48 \text{ months}

Now, we can plug these values into the formula:

M=180000.0043333(1+0.0043333)48(1+0.0043333)481 M = \frac{18000 \cdot 0.0043333 \cdot (1 + 0.0043333)^{48}}{(1 + 0.0043333)^{48} - 1}

First, calculate (1+0.0043333)48(1 + 0.0043333)^{48}:

(1+0.0043333)481.221386 (1 + 0.0043333)^{48} \approx 1.221386

Now, calculate the numerator:

180000.00433331.22138695.276 18000 \cdot 0.0043333 \cdot 1.221386 \approx 95.276

And the denominator:

1.2213861=0.221386 1.221386 - 1 = 0.221386

Finally, calculate the monthly payment:

M=95.2760.221386430.36 M = \frac{95.276}{0.221386} \approx 430.36

So, Deandre's monthly payment is approximately $430.36.

(b) To find the total amount to repay the loan, we multiply the monthly payment by the total number of payments:

Total repayment=M×n=430.36×4820657.28 \text{Total repayment} = M \times n = 430.36 \times 48 \approx 20657.28

So, the total amount to repay the loan is approximately $20,657.28.

(c) To find the total amount of interest Deandre will pay, we subtract the loan principal from the total repayment amount:

Total interest=Total repaymentP=20657.28180002657.28 \text{Total interest} = \text{Total repayment} - P = 20657.28 - 18000 \approx 2657.28

So, the total amount of interest Deandre will pay is approximately $2,657.28.

This problem has been solved

Solution 3

(a) To find Deandre's monthly payment, we use the formula for the monthly payment on an amortized loan:

M=Pr(1+r)n(1+r)n1 M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1}

where:

  • M M is the monthly payment,
  • P P is the loan principal ($18,000),
  • r r is the monthly interest rate (annual rate divided by 12),
  • n n is the total number of payments (loan term in months).

First, we need to find the monthly interest rate:

r=5.2%12=0.05212=0.0043333 r = \frac{5.2\%}{12} = \frac{0.052}{12} = 0.0043333

Next, we calculate the total number of payments:

n=4 years×12 months/year=48 months n = 4 \text{ years} \times 12 \text{ months/year} = 48 \text{ months}

Now, we can plug these values into the formula:

M=180000.0043333(1+0.0043333)48(1+0.0043333)481 M = \frac{18000 \cdot 0.0043333 \cdot (1 + 0.0043333)^{48}}{(1 + 0.0043333)^{48} - 1}

First, calculate (1+0.0043333)48(1 + 0.0043333)^{48}:

(1+0.0043333)481.221386 (1 + 0.0043333)^{48} \approx 1.221386

Now, calculate the numerator:

180000.00433331.22138695.199 18000 \cdot 0.0043333 \cdot 1.221386 \approx 95.199

And the denominator:

1.2213861=0.221386 1.221386 - 1 = 0.221386

Finally, calculate the monthly payment:

M=95.1990.221386430.07 M = \frac{95.199}{0.221386} \approx 430.07

So, Deandre's monthly payment is approximately $430.07.

(b) To find the total amount Deandre will repay over the term of the loan, we multiply the monthly payment by the number of payments:

Total repayment=M×n=430.07×4820643.36 \text{Total repayment} = M \times n = 430.07 \times 48 \approx 20643.36

So, the total amount to repay the loan is approximately $20,643.36.

(c) To find the total amount of interest Deandre will pay, we subtract the loan principal from the total repayment amount:

Total interest=Total repaymentP=20643.36180002643.36 \text{Total interest} = \text{Total repayment} - P = 20643.36 - 18000 \approx 2643.36

So, the total amount of interest he will pay is approximately $2,643.36.

This problem has been solved

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