What is the electrical efficiency of a 100 Wlight bulb that produces 5.7 kJ (57 000 J) ofheat when it is on for 10 min? (Hint: remem-ber that the bulb is supposed to producelight.) Show your work

To find the electrical efficiency of the light bulb, we need to calculate the ratio of the useful output energy (light) to the input energy (electrical energy).

Step 1: Convert the given power of the light bulb from watts to joules per second. Since 1 watt is equal to 1 joule per second, the power of the light bulb is 100 J/s.

Step 2: Calculate the total energy consumed by the light bulb. The total energy consumed can be found by multiplying the power of the light bulb by the time it is on. In this case, the time is given as 10 minutes, which is equal to 600 seconds. Total energy consumed = Power × Time = 100 J/s × 600 s = 60,000 J

Step 3: Calculate the electrical efficiency. The electrical efficiency is the ratio of the useful output energy (light) to the input energy (electrical energy). Electrical efficiency = (Useful output energy / Input energy) × 100% Useful output energy = Heat produced = 57,000 J

Electrical efficiency = (57,000 J / 60,000 J) × 100% = 95%

Therefore, the electrical efficiency of the 100 W light bulb is 95%.