(sec A + tan A) (1 – sin A) equals:
Question
(sec A + tan A) (1 – sin A) equals:
Solution
To solve the given expression, let's break it down step by step:
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Start with the expression: (sec A + tan A) (1 – sin A)
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Rewrite sec A as 1/cos A: (1/cos A + tan A) (1 – sin A)
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Simplify the expression by finding a common denominator for the terms in the numerator: (1 + cos A sin A / cos A) (1 – sin A)
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Combine the terms in the numerator: (1 + cos A sin A) (1 – sin A)
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Expand the expression using the distributive property: 1 - sin A + cos A sin A - sin^2 A
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Simplify further by combining like terms: 1 - sin A + cos A sin A - sin^2 A
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Rearrange the terms: 1 - sin^2 A + cos A sin A - sin A
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Use the identity sin^2 A + cos^2 A = 1 to replace sin^2 A with 1 - cos^2 A: 1 - (1 - cos^2 A) + cos A sin A - sin A
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Simplify the expression: 1 - 1 + cos^2 A + cos A sin A - sin A
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Combine like terms: cos^2 A + cos A sin A - sin A
Therefore, the expression (sec A + tan A) (1 – sin A) simplifies to cos^2 A + cos A sin A - sin A.
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