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The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds.The probability of a player weighing more than 241.25 pounds is Group of answer choices0.90100.45050.95050.0495

Question

The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds.The probability of a player weighing more than 241.25 pounds is Group of answer choices0.90100.45050.95050.0495

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Solution

To solve this problem, we need to use the concept of Z-score in statistics. The Z-score is a measure of how many standard deviations an element is from the mean.

Step 1: Identify the mean, standard deviation, and the value for which we need to find the probability. Here, mean (μ) = 200 pounds, standard deviation (σ) = 25 pounds, and the value (X) = 241.25 pounds.

Step 2: Calculate the Z-score using the formula: Z = (X - μ) / σ. Substituting the given values, we get Z = (241.25 - 200) / 25 = 1.65.

Step 3: Look up this Z-score in the standard normal distribution table, or use a calculator or software that can calculate it. The value you find is the probability that the weight is less than 241.25 pounds.

Step 4: Since we want the probability that the weight is more than 241.25 pounds, we subtract the value found in step 3 from 1 (because the total probability under the normal curve is 1).

The Z-score of 1.65 corresponds to a probability of 0.9505. So, the probability of a player weighing more than 241.25 pounds is 1 - 0.9505 = 0.0495.

So, the correct answer is 0.0495.

This problem has been solved

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