The problem is asking to find the total number of pairs in an array such that the absolute difference of the indices is equal to the absolute difference of the elements at those indices.

Here is a Python solution using a dictionary to keep track of the indices of each element in the array:

```python
def solve(arr):
indices = {}
for i, num in enumerate(arr):
if num not in indices:
indices[num] = [i]
else:
indices[num].append(i)
pairs = 0
for index in indices.values():
for i in range(len(index)):
for j in range(i+1, len(index)):
if abs(index[i] - index[j]) == abs(arr[index[i]] - arr[index[j]]):
pairs += 1
return pairs

if __name__ == '__main__':
arr_count = int(input().strip())
arr = list(map(int, input().rstrip().split()))
result = solve(arr)
print(result)
```

This solution works by iterating over the array and storing the indices of each element in a dictionary. Then, for each list of indices in the dictionary, it checks every pair of indices to see if the absolute difference of the indices is equal to the absolute difference of the elements at those indices. If it is, it increments a counter. Finally, it returns the counter.

Question

The problem is asking to find the total number of pairs in an array such that the absolute difference of the indices is equal to the absolute difference of the elements at those indices.

Here is a Python solution using a dictionary to keep track of the indices of each element in the array:

```python
def solve(arr):
    indices = {}
    for i, num in enumerate(arr):
        if num not in indices:
            indices[num] = [i]
        else:
            indices[num].append(i)
    pairs = 0
    for index in indices.values():
        for i in range(len(index)):
            for j in range(i+1, len(index)):
                if abs(index[i] - index[j]) == abs(arr[index[i]] - arr[index[j]]):
                    pairs += 1
    return pairs

if __name__ == '__main__':
    arr_count = int(input().strip())
    arr = list(map(int, input().rstrip().split()))
    result = solve(arr)
    print(result)
```

This solution works by iterating over the array and storing the indices of each element in a dictionary. Then, for each list of indices in the dictionary, it checks every pair of indices to see if the absolute difference of the indices is equal to the absolute difference of the elements at those indices. If it is, it increments a counter. Finally, it returns the counter.

Knowee AI · Accepted Answer

The problem is asking to find the total number of pairs in an array such that the absolute difference of the indices is equal to the absolute difference of the elements at those indices.

Here is a Python solution using a dictionary to keep track of the indices of each element in the array:

```python
def solve(arr):
    indices = {}
    for i, num in enumerate(arr):
        if num not in indices:
            indices[num] = [i]
        else:
            indices[num].append(i)
    pairs = 0
    for index in indices.values():
        for i in range(len(index)):
            for j in range(i+1, len(index)):
                if abs(index[i] - index[j]) == abs(arr[index[i]] - arr[index[j]]):
                    pairs += 1
    return pairs

if __name__ == '__main__':
    arr_count = int(input().strip())
    arr = list(map(int, input().rstrip().split()))
    result = solve(arr)
    print(result)
```

This solution works by iterating over the array and storing the indices of each element in a dictionary. Then, for each list of indices in the dictionary, it checks every pair of indices to see if the absolute difference of the indices is equal to the absolute difference of the elements at those indices. If it is, it increments a counter. Finally, it returns the counter.

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