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Given two integers a and b, write a function lcmAndGcd() to compute their LCM and GCD. The function takes two integers a and b as input and returns a list containing their LCM and GCD.Example 1:Input: a = 5 , b = 10Output: 10 5Explanation: LCM of 5 and 10 is 10, while thier GCD is 5.Input: a = 14 , b = 8Output: 56 2Explanation: LCM of 14 and 8 is 56, while thier GCD is 2.Expected Time Complexity: O(log(min(a, b))Expected Auxiliary Space: O(1)Constraints:

Question

Given two integers a and b, write a function lcmAndGcd() to compute their LCM and GCD. The function takes two integers a and b as input and returns a list containing their LCM and GCD.Example 1:Input: a = 5 , b = 10Output: 10 5Explanation: LCM of 5 and 10 is 10, while thier GCD is 5.Input: a = 14 , b = 8Output: 56 2Explanation: LCM of 14 and 8 is 56, while thier GCD is 2.Expected Time Complexity: O(log(min(a, b))Expected Auxiliary Space: O(1)Constraints:

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Solution

Sure, here is a Python function that calculates the LCM and GCD of two numbers:

def gcd(a, b):
    if a == 0:
        return b
    return gcd(b % a, a)

def lcm(a, b):
    return (a / gcd(a, b)) * b

def lcmAndGcd(a, b):
    return [lcm(a, b), gcd(a, b)]

Here's how it works:

  1. The gcd function uses the Euclidean algorithm to find the greatest common divisor of a and b. If a is 0, it returns b. Otherwise, it recursively calls itself with b % a and a.

  2. The lcm function calculates the least common multiple of a and b by dividing a by their GCD and then multiplying by b. This works because a * b = lcm(a, b) * gcd(a, b).

  3. The lcmAndGcd function returns a list containing the LCM and GCD of a and b.

The time complexity of this function is O(log(min(a, b))) because the Euclidean algorithm runs in logarithmic time. The auxiliary space complexity is O(1) because it uses a constant amount of space.

This problem has been solved

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