1 pointWhat is the output of the following code?i = 1while True:    if i%2 == 0:        break    print(i)    i += 211 21 2 3 4 5 6 ...1 3 5 7 9 11 ...

The output of the given code will be "1".

Here's the step by step explanation:

1. The variable i is initialized with the value 1.
2. The while True: statement starts an infinite loop.
3. The if i%2 == 0: statement checks if i is divisible by 2 (i.e., if i is an even number). If i is even, the break statement will be executed, which will terminate the loop.
4. If i is not even (i.e., i is an odd number), the program will print the value of i and then increment i by 2.
5. Since i is initially 1 (an odd number), the program will print "1" and then increment i to 3.
6. However, when the loop starts again, i is now 3. The if i%2 == 0: statement will be false because 3 is not divisible by 2. So, the break statement will not be executed.
7. But, there's no print statement after the if condition. So, nothing will be printed in the next iterations and the loop will continue infinitely without printing anything else.
8. Therefore, the only output of this code will be the first printed value, which is "1".