To test if the time required to dissolve the drug piles of three dugs in a same, certain solution is the test is done on different piles. The data is obtained as below. Drug A -16, 8, 10, 12, 12, 14 Drug B - 12, 10, 11,9, 13 Drug C - 5, 8,12, 10,9, 11 Test if all 3 drugs required same time to dissolve in the solution with Kruskal-Wall test. (Critical Val=s.99)

To perform the Kruskal-Wallis test, follow these steps:

Step 1: Rank all data from all groups together; i.e., rank the data from smallest to largest, ignore which group they belong to. If there are any ties, assign each tied value the average of the ranks they would have received had they not been tied.

For Drug A: 8, 10, 12, 12, 14, 16 For Drug B: 9, 10, 11, 12, 13 For Drug C: 5, 8, 9, 10, 11, 12

Step 2: Calculate the sum of ranks for each group.

For Drug A: 2 + 3 + 7.5 + 7.5 + 11 + 15 = 46 For Drug B: 4 + 3 + 6 + 7.5 + 12 = 32.5 For Drug C: 1 + 2 + 4 + 3 + 6 + 7.5 = 23.5

Step 3: Calculate the test statistic H. The formula for H is:

H = (12 / (n(n+1))) [ ΣRi^2/ni ] - 3(n + 1)

where n is the total sample size (number of all observations), ni is the size of the i-th sample (number of observations in the i-th group), and Ri is the sum of ranks in the i-th group.

H = (12 / (17*18)) [(46^2/6) + (32.5^2/5) + (23.5^2/6)] - 3(18)

Step 4: Compare the calculated H value with the critical value from the Chi-Square distribution table. The degrees of freedom is k-1, where k is the number of groups. If the calculated H value is greater than the critical value, reject the null hypothesis that all 3 drugs required the same time to dissolve in the solution.

Note: The actual calculation of H and comparison with the critical value is not provided here as it requires a calculator or statistical software.