3 × {4 – 8 [6 × (9 – 5) – 5 × (28 ÷ 7)] + 1}
Question
3 × {4 – 8 [6 × (9 – 5) – 5 × (28 ÷ 7)] + 1}
Solution
Sure, let's solve this step by step:
First, we need to solve the operations inside the parentheses:
9 - 5 = 4 28 ÷ 7 = 4
So the equation becomes:
3 × {4 - 8 [6 × 4 - 5 × 4] + 1}
Next, we need to solve the operations inside the brackets:
6 × 4 = 24 5 × 4 = 20
So the equation becomes:
3 × {4 - 8 [24 - 20] + 1}
Then, we solve the operation inside the brackets:
24 - 20 = 4
So the equation becomes:
3 × {4 - 8 × 4 + 1}
Next, we solve the multiplication:
8 × 4 = 32
So the equation becomes:
3 × {4 - 32 + 1}
Then, we solve the operations inside the curly brackets:
4 - 32 + 1 = -27
So the equation becomes:
3 × -27
Finally, we solve the multiplication:
3 × -27 = -81
So, the answer is -81.
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