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3 × {4 – 8 [6 × (9 – 5) – 5 × (28 ÷ 7)] + 1}

Question

3 × {4 – 8 [6 × (9 – 5) – 5 × (28 ÷ 7)] + 1}

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Solution

Sure, let's solve this step by step:

First, we need to solve the operations inside the parentheses:

9 - 5 = 4 28 ÷ 7 = 4

So the equation becomes:

3 × {4 - 8 [6 × 4 - 5 × 4] + 1}

Next, we need to solve the operations inside the brackets:

6 × 4 = 24 5 × 4 = 20

So the equation becomes:

3 × {4 - 8 [24 - 20] + 1}

Then, we solve the operation inside the brackets:

24 - 20 = 4

So the equation becomes:

3 × {4 - 8 × 4 + 1}

Next, we solve the multiplication:

8 × 4 = 32

So the equation becomes:

3 × {4 - 32 + 1}

Then, we solve the operations inside the curly brackets:

4 - 32 + 1 = -27

So the equation becomes:

3 × -27

Finally, we solve the multiplication:

3 × -27 = -81

So, the answer is -81.

This problem has been solved

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