The pseudocode provided is a recursive function. Here's how it works:

1. The function `funn` is called with `a = 4` and `b = 6`.
2. The `if` condition checks if `a 1`. Since `a = 4`, the condition is true.
3. The function then returns `a * funn(b - 6, a - 4)`. This means it will return `4 * funn(0, 0)`.
4. Now, the function `funn` is called again with `a = 0` and `b = 0`.
5. The `if` condition checks if `a 1`. Since `a = 0`, the condition is false.
6. The function then returns `1`.
7. Going back to step 3, the function now returns `4 * 1 = 4`.

So, the output of the pseudocode for `a = 4` and `b = 6` is `4`. Therefore, the correct answer is C. 4.

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The pseudocode provided is a recursive function. Here's how it works:

1. The function `funn` is called with `a = 4` and `b = 6`.
2. The `if` condition checks if `a > 1`. Since `a = 4`, the condition is true.
3. The function then returns `a * funn(b - 6, a - 4)`. This means it will return `4 * funn(0, 0)`.
4. Now, the function `funn` is called again with `a = 0` and `b = 0`.
5. The `if` condition checks if `a > 1`. Since `a = 0`, the condition is false.
6. The function then returns `1`.
7. Going back to step 3, the function now returns `4 * 1 = 4`.

So, the output of the pseudocode for `a = 4` and `b = 6` is `4`. Therefore, the correct answer is C. 4.

Knowee AI · Accepted Answer

The pseudocode provided is a recursive function. Here's how it works:

1. The function `funn` is called with `a = 4` and `b = 6`.
2. The `if` condition checks if `a > 1`. Since `a = 4`, the condition is true.
3. The function then returns `a * funn(b - 6, a - 4)`. This means it will return `4 * funn(0, 0)`.
4. Now, the function `funn` is called again with `a = 0` and `b = 0`.
5. The `if` condition checks if `a > 1`. Since `a = 0`, the condition is false.
6. The function then returns `1`.
7. Going back to step 3, the function now returns `4 * 1 = 4`.

So, the output of the pseudocode for `a = 4` and `b = 6` is `4`. Therefore, the correct answer is C. 4.

What will be the output of the following pseudocode for a = 4, b = 6?Integer funn(Integer a, Integer b) If(a > 1) Return a * funn (b - 6, a - 4) Else Return 1 End If Return a + b End function funn()Question 79AnswerA.7B.17C.4D.0

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