The minimum number of moles of O2O2 required for complete combustion of 1 mole of propane and 2 moles of butane is..............(Nearest integer)
Question
The minimum number of moles of O2O2 required for complete combustion of 1 mole of propane and 2 moles of butane is..............(Nearest integer)
Solution
The combustion reactions for propane (C3H8) and butane (C4H10) are as follows:
C3H8 + 5O2 -> 3CO2 + 4H2O C4H10 + 6.5O2 -> 4CO2 + 5H2O
From these reactions, we can see that 1 mole of propane requires 5 moles of O2 for complete combustion and 1 mole of butane requires 6.5 moles of O2 for complete combustion.
Therefore, for the complete combustion of 1 mole of propane and 2 moles of butane, we would need:
(1 mole of propane x 5 moles of O2) + (2 moles of butane x 6.5 moles of O2) = 5 + 13 = 18 moles of O2
So, the minimum number of moles of O2 required for complete combustion of 1 mole of propane and 2 moles of butane is 18 (to the nearest integer).
Similar Questions
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