32 The circuit diagrams show two lamps X and Y each connected to a cell. The current in lamp X is0.50 A and its resistance is 9.6 . The current in lamp Y is 3.0 A and its resistance is 1.2 .0.50 A lamp X9.6 3.0 A lamp Y1.2 What is the ratio YlampinpowerXlampinpower ?A 0.22 B 0.75 C 1.3 D 4.533 The intensity of light incident on a light-dependent resistor (LDR) is increased. The temperatureof a thermistor is increased. In each case, the current in the component is maintained at aconstant value.What happens to the potential difference across each component?LDR thermistorA increases increasesB increases decreasesC decreases increasesD decreases decreases34 An iron wire has length 8.0 m and diameter 0.50 mm. The wire has resistance R.A second iron wire has length 2.0 m and diameter 1.0 mm.What is the resistance of the second wire?A 16R B 8R C 2R D R35 A cell with constant electromotive force (e.m.f.) is connected across a fixed resistor. Over time,the internal resistance of the cell increases.Which change occurs as the internal resistance of the cell increases?A a decrease in the charge of each charge carrierB a decrease in the potential difference measured across the cellC an increase in the energy dissipated per unit time in the fixed resistorD an increase in the number of charge carriers leaving the cell per unit time
Question
32 The circuit diagrams show two lamps X and Y each connected to a cell. The current in lamp X is0.50 A and its resistance is 9.6 . The current in lamp Y is 3.0 A and its resistance is 1.2 .0.50 A lamp X9.6 3.0 A lamp Y1.2 What is the ratio YlampinpowerXlampinpower ?A 0.22 B 0.75 C 1.3 D 4.533 The intensity of light incident on a light-dependent resistor (LDR) is increased. The temperatureof a thermistor is increased. In each case, the current in the component is maintained at aconstant value.What happens to the potential difference across each component?LDR thermistorA increases increasesB increases decreasesC decreases increasesD decreases decreases34 An iron wire has length 8.0 m and diameter 0.50 mm. The wire has resistance R.A second iron wire has length 2.0 m and diameter 1.0 mm.What is the resistance of the second wire?A 16R B 8R C 2R D R35 A cell with constant electromotive force (e.m.f.) is connected across a fixed resistor. Over time,the internal resistance of the cell increases.Which change occurs as the internal resistance of the cell increases?A a decrease in the charge of each charge carrierB a decrease in the potential difference measured across the cellC an increase in the energy dissipated per unit time in the fixed resistorD an increase in the number of charge carriers leaving the cell per unit time
Solution
The text you provided contains multiple questions. Here are the answers to each one:
- To find the ratio of power in lamp Y to lamp X, we first need to calculate the power of each lamp. Power (P) is calculated by the formula P = I^2 * R, where I is the current and R is the resistance.
For lamp X: P = (0.50 A)^2 * 9.6 Ω = 2.4 W For lamp Y: P = (3.0 A)^2 * 1.2 Ω = 10.8 W
The ratio of power in lamp Y to lamp X is therefore 10.8 W / 2.4 W = 4.5. So, the answer is D, 4.5.
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When the intensity of light incident on a light-dependent resistor (LDR) is increased, the resistance decreases, which would increase the potential difference across the component. When the temperature of a thermistor is increased, its resistance decreases, which would also increase the potential difference across the component. So, the answer is A, increases for both.
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The resistance of a wire is given by the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. If the length is halved and the diameter is doubled, the resistance would be halved. So, the answer is C, 2R.
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If the internal resistance of a cell increases, the potential difference across the cell would decrease because more voltage would be dropped across the internal resistance. So, the answer is B, a decrease in the potential difference measured across the cell.
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