To solve this problem, we can use the Gay-Lussac's Law which states that the pressure of a gas is directly proportional to its absolute temperature, if the volume and the amount of gas remain constant. The formula for Gay-Lussac's Law is P1/T1 = P2/T2.

Here's the step-by-step solution:

Step 1: Convert all temperatures to Kelvin. The Kelvin scale is the standard unit of temperature in physics.

T1 = 25°C + 273.15 = 298.15 K
T2 = 475°C + 273.15 = 748.15 K

Step 2: Substitute the given values into the Gay-Lussac's Law formula.

(182 kPa / 298.15 K) = P2 / 748.15 K

Step 3: Solve for P2.

P2 = (182 kPa / 298.15 K) * 748.15 K
P2 = 455.6 kPa

So, if the aerosol can were heated to 475°C, the pressure would develop to approximately 455.6 kPa.

Question

To solve this problem, we can use the Gay-Lussac's Law which states that the pressure of a gas is directly proportional to its absolute temperature, if the volume and the amount of gas remain constant. The formula for Gay-Lussac's Law is P1/T1 = P2/T2.

Here's the step-by-step solution:

Step 1: Convert all temperatures to Kelvin. The Kelvin scale is the standard unit of temperature in physics.

T1 = 25°C + 273.15 = 298.15 K
T2 = 475°C + 273.15 = 748.15 K

Step 2: Substitute the given values into the Gay-Lussac's Law formula.

(182 kPa / 298.15 K) = P2 / 748.15 K

Step 3: Solve for P2.

P2 = (182 kPa / 298.15 K) * 748.15 K
P2 = 455.6 kPa

So, if the aerosol can were heated to 475°C, the pressure would develop to approximately 455.6 kPa.

Knowee AI · Accepted Answer

To solve this problem, we can use the Gay-Lussac's Law which states that the pressure of a gas is directly proportional to its absolute temperature, if the volume and the amount of gas remain constant. The formula for Gay-Lussac's Law is P1/T1 = P2/T2.

Here's the step-by-step solution:

Step 1: Convert all temperatures to Kelvin. The Kelvin scale is the standard unit of temperature in physics.

T1 = 25°C + 273.15 = 298.15 K
T2 = 475°C + 273.15 = 748.15 K

Step 2: Substitute the given values into the Gay-Lussac's Law formula.

(182 kPa / 298.15 K) = P2 / 748.15 K

Step 3: Solve for P2.

P2 = (182 kPa / 298.15 K) * 748.15 K
P2 = 455.6 kPa

So, if the aerosol can were heated to 475°C, the pressure would develop to approximately 455.6 kPa.

Question 4Not yet answeredMarked out of 1.00Flag questionTipsThe gas pressure in an aerosol can is 182 kPa at 25oC. If the gasis an ideal gas, what pressure would develop in the can if it wereheated to 475oC?

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