Tin-129 is radioactive and has a half life of 2.23 minutes. What percentage of a sample would be left after 10.6 minutes?Round your answer to 2 significant digits.
Question
Tin-129 is radioactive and has a half life of 2.23 minutes. What percentage of a sample would be left after 10.6 minutes?Round your answer to 2 significant digits.
Solution
To solve this problem, we need to use the formula for exponential decay which is:
N = N0 * (1/2)^(t/T)
where: N is the final amount of the substance, N0 is the initial amount of the substance, t is the time that has passed, and T is the half-life of the substance.
In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 10.6 minutes and T = 2.23 minutes.
So, we substitute these values into the formula:
N/N0 = (1/2)^(10.6/2.23)
Calculating the exponent first:
10.6/2.23 = 4.75 (approximately)
Then, we calculate the fraction:
N/N0 = (1/2)^4.75 = 0.027 (approximately)
To express this as a percentage, we multiply by 100:
0.027 * 100 = 2.7%
So, approximately 2.7% of the Tin-129 sample would be left after 10.6 minutes.
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