Problem StatementGiven three integers A, B, C where 'A' denotes the first term of an arithmetic sequence, 'C' denotes the common difference between an arithmetic sequence and an integer 'B'. You need to tell whether 'B' exists in the arithmetic sequence or not. Return 1 if B is present in the sequence. Otherwise, return 0. Example 1Input: A = 1, B = 3, C = 2Output: 1Explanation: 3 is the second term of the sequence starting with 1 and having a common difference of 2.Example 2Input: A = 1, B = 2, C = 3Output: 0Explanation: 2 is not present in the sequence. Example 3Input: A = 2, B = 4, C = 0Output: 0Explanation: In arithmetic progression starting from 2 with common difference 0, 4 cannot be reached since the sequence remains constant. Hence, the output is 0.Note: This question was used in the FactSet coding test.Input format :The input consists of three space-separated integers values A, B, and C, representing the first term 'A' of the arithmetic sequence, 'B' to check, and the common difference 'C' of the arithmetic sequence.Output format :The output displays 1 if 'B' is present in the arithmetic sequence, otherwise, it displays 0.Refer to the sample output for the formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:-100 ≤ A, B, C ≤ 100Sample test cases :Input 1 :1 3 2Output 1 :1Input 2 :1 2 3Output 2 :0Input 3 :-3 -9 -3Output 3 :1Input 4 :2 4 0Output 4 :0

def is_in_sequence(A, B, C):
    if C == 0:
        return int(A == B)
    else:
        n = (B - A) / C + 1
        return int(n > 0 and n == int(n))

print(is_in_sequence(1, 3, 2))  # Output: 1
print(is_in_sequence(1, 2, 3))  # Output: 0
print(is_in_sequence(-3, -9, -3))  # Output: