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7. Find the gradient for the function ๐‘ข = ๐œ‘(๐‘Ÿ), ๐‘Ÿ = โˆš๐‘ฅ2 + ๐‘ฆ2 + ๐‘ง2.Answer: ๐›๐‘ข = ๐œ‘โ€ฒ(๐‘Ÿ) ๐’“๐‘Ÿ .

Question

  1. Find the gradient for the function ๐‘ข = ๐œ‘(๐‘Ÿ), ๐‘Ÿ = โˆš๐‘ฅ2 + ๐‘ฆ2 + ๐‘ง2.Answer: ๐›๐‘ข = ๐œ‘โ€ฒ(๐‘Ÿ) ๐’“๐‘Ÿ .
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Solution

To find the gradient of the function u = ฯ†(r), where r = โˆš(xยฒ + yยฒ + zยฒ), we need to use the chain rule for differentiation.

Step 1: Differentiate ฯ†(r) with respect to r to get ฯ†โ€ฒ(r).

Step 2: Differentiate r with respect to x, y, and z to get the vector (x/r, y/r, z/r). This is the unit vector in the direction of r, denoted as ๐’“๐‘Ÿ.

Step 3: Multiply ฯ†โ€ฒ(r) by ๐’“๐‘Ÿ to get the gradient of u, which is ๐›๐‘ข = ฯ†โ€ฒ(r) ๐’“๐‘Ÿ.

So, the gradient of the function u = ฯ†(r), where r = โˆš(xยฒ + yยฒ + zยฒ), is ๐›๐‘ข = ฯ†โ€ฒ(r) ๐’“๐‘Ÿ.

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