What will be the output of the following code snippet for the list 1->2->3->4->5->6?def fun(start): if start is None: return print(start.data, end=" ") if start.next is not None: fun(start.next.next) print(start.data, end=" ")Options2 4 6 1 3 51 3 5 5 3 11 2 3 4 5 61 3 5 1 3 5

The output of the given code snippet will be "1 3 5 5 3 1".

Here's the step by step explanation:

1. The function fun() is a recursive function that prints the data of the nodes of a linked list.

2. The base case of the recursion is when the start node is None, in which case the function returns without printing anything.

3. If the start node is not None, the function first prints the data of the start node.

4. Then, if the next node of the start node is not None, the function calls itself with the node two steps ahead of the start node as the argument.

5. After the recursive call, the function prints the data of the start node again.

6. For the linked list 1->2->3->4->5->6, the function is initially called with the first node (with data 1) as the argument.

7. The function prints "1 ", then calls itself with the third node (with data 3) as the argument.

8. The function prints "3 ", then calls itself with the fifth node (with data 5) as the argument.

9. The function prints "5 ", then calls itself with None as the argument.

10. Since the argument is None, the function returns without printing anything.

11. The function then prints "5 " again, and returns to the previous call.

12. The function then prints "3 " again, and returns to the previous call.

13. Finally, the function prints "1 " again, and returns to the original call.

So, the output of the code snippet is "1 3 5 5 3 1".