The frequency of vibration for a piezoelectric oscillator can be calculated using the formula:

f = v / 2d

where:
f is the frequency,
v is the velocity of the longitudinal waves in the quartz crystal, and
d is the thickness of the quartz crystal.

Given that the velocity v is 5.5 x 10^3 m/s and the thickness d is 0.05 m, we can substitute these values into the formula to find the frequency of the first mode of vibration:

f1 = (5.5 x 10^3 m/s) / (2 * 0.05 m) = 55,000 Hz or 55 kHz

However, the question asks for the frequency of the second mode of vibration. In many oscillating systems, the frequency of the nth mode of vibration is n times the frequency of the first mode. Therefore, the frequency of the second mode of vibration would be:

f2 = 2 * f1 = 2 * 55,000 Hz = 110,000 Hz or 110 kHz

So, the frequency of the second mode of vibration for the quartz of the piezoelectric oscillator is 110,000 Hz or 110 kHz.

Question

The frequency of vibration for a piezoelectric oscillator can be calculated using the formula:

f = v / 2d

where:
f is the frequency,
v is the velocity of the longitudinal waves in the quartz crystal, and
d is the thickness of the quartz crystal.

Given that the velocity v is 5.5 x 10^3 m/s and the thickness d is 0.05 m, we can substitute these values into the formula to find the frequency of the first mode of vibration:

f1 = (5.5 x 10^3 m/s) / (2 * 0.05 m) = 55,000 Hz or 55 kHz

However, the question asks for the frequency of the second mode of vibration. In many oscillating systems, the frequency of the nth mode of vibration is n times the frequency of the first mode. Therefore, the frequency of the second mode of vibration would be:

f2 = 2 * f1 = 2 * 55,000 Hz = 110,000 Hz or 110 kHz

So, the frequency of the second mode of vibration for the quartz of the piezoelectric oscillator is 110,000 Hz or 110 kHz.

Knowee AI · Accepted Answer

The frequency of vibration for a piezoelectric oscillator can be calculated using the formula:

f = v / 2d

where:
f is the frequency,
v is the velocity of the longitudinal waves in the quartz crystal, and
d is the thickness of the quartz crystal.

Given that the velocity v is 5.5 x 10^3 m/s and the thickness d is 0.05 m, we can substitute these values into the formula to find the frequency of the first mode of vibration:

f1 = (5.5 x 10^3 m/s) / (2 * 0.05 m) = 55,000 Hz or 55 kHz

However, the question asks for the frequency of the second mode of vibration. In many oscillating systems, the frequency of the nth mode of vibration is n times the frequency of the first mode. Therefore, the frequency of the second mode of vibration would be:

f2 = 2 * f1 = 2 * 55,000 Hz = 110,000 Hz or 110 kHz

So, the frequency of the second mode of vibration for the quartz of the piezoelectric oscillator is 110,000 Hz or 110 kHz.

The frequency of second mode of vibration for a quartz ofpiezoelectric oscillator is _____ Hz if the velocity of longitudinalwaves in quartz crystal is 5.5 x 10^3 m/s and thickness of quartzcrystal is 0.05 m

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