Calculate concentration in ppb of 1500. mL water containing 0.000300 g Lead ion.Group of answer choices500. ppm5.00 x 10^6 ppb200. ppb2.00 x 10^-7 ppb
Question
Calculate concentration in ppb of 1500. mL water containing 0.000300 g Lead ion.Group of answer choices500. ppm5.00 x 10^6 ppb200. ppb2.00 x 10^-7 ppb
Solution
To calculate the concentration in ppb (parts per billion), you need to follow these steps:
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First, convert the mass of Lead ion from grams to micrograms, because 1 ppb is equivalent to 1 microgram per liter. So, 0.000300 g is equal to 0.000300 * 10^6 = 300 micrograms.
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Then, convert the volume of water from mL to L, because the concentration is usually expressed in terms of liters. So, 1500 mL is equal to 1.5 L.
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Finally, calculate the concentration in ppb using the formula: Concentration (ppb) = (mass of solute (micrograms) / volume of solution (L)). So, the concentration of Lead ion in the water is 300 micrograms / 1.5 L = 200 ppb.
So, the correct answer is 200 ppb.
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