Let M and N be two entities in an E-R diagram with simple single value attributes. R1 and R2 are two relationship between M and N, where as R1 is one-to-many and R2 is many-to-many. The minimum number of tables required to represent M, N, R1 and R2 in the relational model are _______.
Question
Let M and N be two entities in an E-R diagram with simple single value attributes. R1 and R2 are two relationship between M and N, where as R1 is one-to-many and R2 is many-to-many. The minimum number of tables required to represent M, N, R1 and R2 in the relational model are _______.
Solution
To represent M, N, R1, and R2 in the relational model, we would need a minimum of 4 tables.
Here's why:
- One table for entity M.
- One table for entity N.
- One table for relationship R1. Since R1 is a one-to-many relationship, we can represent it by adding a foreign key in the "many" side entity (N in this case) pointing to the "one" side entity (M in this case). However, to keep the count of tables explicit, we are considering it as a separate table.
- One table for relationship R2. Since R2 is a many-to-many relationship, it requires a separate table to represent it. This table would typically contain foreign keys pointing to both M and N.
So, the minimum number of tables required would be 4.
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