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Predict the output:interface Employee {       int a=90;       }class PermanentEmployee implements Employee {                    public void f1()       {                a=10;        }}Select one:a.error, since interfaces Employee is not publicb.error, since variable a is defaultc.error, since variable a is assigned a valued.no error

Question

Predict the output:interface Employee {       int a=90;       }class PermanentEmployee implements Employee {                    public void f1()       {                a=10;        }}Select one:a.error, since interfaces Employee is not publicb.error, since variable a is defaultc.error, since variable a is assigned a valued.no error

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Solution

The correct answer is:

c. error, since variable a is assigned a value

Explanation:

In Java, the fields in an interface are implicitly public, static, and final. This means they cannot be modified. They are constants. So, when you try to assign a new value to 'a' in the PermanentEmployee class, it will result in a compile-time error. Therefore, you cannot change the value of 'a' as it is declared in an interface.

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