What is the other resulting element when Uranium-238 produces a Helium-4 atom?*1 pointThUPNp

Uranium-238 (U-238) undergoes alpha decay to produce a Helium-4 atom (also known as an alpha particle). The process of alpha decay involves the loss of 2 protons and 2 neutrons from the nucleus of the parent atom (U-238 in this case).

Here's the step-by-step process:

1. Identify the atomic number and mass number of the parent atom. Uranium-238 has an atomic number of 92 (which represents the number of protons) and a mass number of 238 (which represents the total number of protons and neutrons).

2. Identify the atomic number and mass number of the alpha particle. An alpha particle (Helium-4) has an atomic number of 2 and a mass number of 4.

3. Subtract the atomic number and mass number of the alpha particle from the atomic number and mass number of the parent atom to find the atomic number and mass number of the resulting atom.

   Resulting atomic number = 92 (Uranium) - 2 (Helium) = 90 Resulting mass number = 238 (Uranium) - 4 (Helium) = 234

4. The resulting atom is the element with atomic number 90, which is Thorium (Th). So, the other resulting element when Uranium-238 produces a Helium-4 atom is Thorium-234.