A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 2m. If the cricket player wants to release the ball such that its velocity is exactly parallel to the ground, and the velocity is actually 40 ms-1. Calculate the total mechanical energy of the cricket ball as it is released? Give your answer to zero decimal places in units of J. Do not include the units in your answer i.e. you would write 13 J as 13

To calculate the total mechanical energy of the cricket ball as it is released, we need to consider both its kinetic energy and its potential energy.

1. First, let's calculate the kinetic energy (KE). The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity. In this case, m = 100g = 0.1kg (since 1g = 0.001kg) and v = 40 m/s. So, KE = 1/2 * 0.1kg * (40 m/s)^2 = 80 Joules.

2. Next, let's calculate the potential energy (PE). The formula for potential energy is PE = m * g * h, where m is the mass of the object, g is the acceleration due to gravity (which is approximately 9.8 m/s^2 on Earth), and h is the height above the ground. In this case, m = 0.1kg, g = 9.8 m/s^2, and h = 2m. So, PE = 0.1kg * 9.8 m/s^2 * 2m = 1.96 Joules.

3. Finally, the total mechanical energy is the sum of the kinetic energy and the potential energy. So, the total mechanical energy = KE + PE = 80 Joules + 1.96 Joules = 81.96 Joules.

Rounding to zero decimal places, the total mechanical energy of the cricket ball as it is released is approximately 82 Joules. So, the answer is 82.

To calculate the total mechanical energy of the cricket ball as it is released, we need to consider both its kinetic energy and its potential energy.

1. First, let's calculate the kinetic energy (KE). The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity. In this case, m = 100g = 0.1kg (since 1g = 0.001kg) and v = 40 m/s. So, KE = 1/2 * 0.1kg * (40 m/s)^2 = 80 Joules.

2. Next, let's calculate the potential energy (PE). The formula for potential energy is PE = m * g * h, where m is the mass of the object, g is the acceleration due to gravity, and h is the height above the ground. In this case, m = 0.1kg, g = 9.8 m/s^2 (the standard value for acceleration due to gravity on Earth), and h = 2m. So, PE = 0.1kg * 9.8 m/s^2 * 2m = 1.96 Joules.

3. Finally, the total mechanical energy is the sum of the kinetic energy and the potential energy. So, the total mechanical energy = KE + PE = 80 Joules + 1.96 Joules = 81.96 Joules.

Rounding to zero decimal places, the total mechanical energy of the cricket ball as it is released is 82 Joules. So, the answer is 82.