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A cube of aluminum is at a depth of 1.00 km under seawater whose density is 1,025 kg/m3. Atmospheric pressure is 101.3 kPa. What is the volume stress on the cube? Use g = 9.80 m/s2.

Question

A cube of aluminum is at a depth of 1.00 km under seawater whose density is 1,025 kg/m3. Atmospheric pressure is 101.3 kPa. What is the volume stress on the cube? Use g = 9.80 m/s2.

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Solution

To calculate the volume stress on the cube, we first need to calculate the pressure at the depth of 1.00 km under seawater.

  1. Calculate the pressure due to the water column above the cube:

    Pressure due to water column = Density of water * g * height = 1025 kg/m^3 * 9.80 m/s^2 * 1000 m = 10,045,000 Pa or 10.045 MPa

  2. Add the atmospheric pressure to the pressure due to the water column to get the total pressure at the depth of the cube:

    Total pressure = Pressure due to water column + Atmospheric pressure = 10.045 MPa + 101.3 kPa = 10.1463 MPa

  3. The volume stress on the cube is equal to the total pressure at the depth of the cube because stress is defined as force per unit area, and pressure is a type of stress that is exerted uniformly in all directions.

    So, the volume stress on the cube = 10.1463 MPa.

This problem has been solved

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