How can we define more than one method in a class differentiated by method signature?Select one:Method overloadingMethod overridingNone of the mentionedMethod doubling

The correct answer is Method overloading.

Method overloading is a feature in Java that allows a class to have more than one method having the same name, if their argument lists are different. It is related to compile-time (or static) polymorphism. The argument list could differ in - number of parameters, type of parameters, or the order of parameters.

Here is a simple example:

class Demo {
    void method(int a) {
        System.out.println("one parameter: " + a);
    }

    void method(int a, int b) {
        System.out.println("two parameters: " + a + ", " + b);
    }

    double method(double a) {
        System.out.println("double parameter: " + a);
        return a*a;
    }
}

public class Main {
    public static void main(String[] args) {
        Demo obj = new Demo();
        double result;
        obj.method(10);
        obj.method(10, 20);
        result = obj.method(5.5);
        System.out.println("Answer is: " + result);
    }
}

In this example, we have three methods named 'method'. The first method takes one integer parameter, the second one takes two integer parameters, and the third one takes one double parameter. Because the number and type of parameters are different,