Knowee
Questions
Features
Study Tools

ind ๐‘๐‘Œ (๐‘ฆ), the marginal p.m.f. of ๐‘Œ

Question

ind ๐‘๐‘Œ (๐‘ฆ), the marginal p.m.f. of ๐‘Œ

๐Ÿง Not the exact question you are looking for?Go ask a question

Solution

To find the marginal p.m.f. of ๐‘Œ, denoted as ๐‘๐‘Œ(๐‘ฆ), we need to follow these steps:

  1. Start with the joint probability mass function (p.m.f.) of ๐‘‹ and ๐‘Œ, denoted as ๐‘(๐‘ฅ, ๐‘ฆ).

  2. Sum up the probabilities of all possible values of ๐‘‹ for each fixed value of ๐‘Œ. This will give us the marginal p.m.f. of ๐‘Œ.

  3. Mathematically, the marginal p.m.f. of ๐‘Œ can be calculated as:

    ๐‘๐‘Œ(๐‘ฆ) = โˆ‘๐‘ฅ ๐‘(๐‘ฅ, ๐‘ฆ)

    where โˆ‘๐‘ฅ represents the summation over all possible values of ๐‘‹.

  4. Repeat this process for each value of ๐‘Œ to obtain the complete marginal p.m.f. of ๐‘Œ.

By following these steps, you can find the marginal p.m.f. of ๐‘Œ, ๐‘๐‘Œ(๐‘ฆ).

This problem has been solved

Similar Questions

b) Find ๐‘๐‘Œ (๐‘ฆ), the marginal p.m.f. of ๐‘Œ

eet the joint p.d.f. of X1 and X2 be:โ„Ž(๐‘ฅ1, ๐‘ฅ2) = {8๐‘ฅ1๐‘ฅ2 for 0 < ๐‘ฅ1 < ๐‘ฅ2 < 10 otherwisea) Find the joint p.d.f. of ๐‘Œ1 = ๐‘‹1๐‘‹2and ๐‘Œ2 = ๐‘‹2b) Are ๐‘Œ1 and ๐‘Œ2 independent? Why? (10 points

For the Joint PMF as shown, find each of following quantities:๐‘๐‘‹ ๐‘ฅ , ๐‘๐‘Œ ๐‘ฆ , ๐‘๐‘‹|๐‘Œ ๐‘ฅ ๐‘ฆ , ๐‘๐‘Œ|๐‘‹ ๐‘ฆ ๐‘ฅ , ๐ธ[๐‘‹|๐‘Œ = 3]Also find whether ๐‘‹ and ๐‘Œ are independent or not.[The graph shows ๐‘๐‘‹,๐‘Œ(๐‘ฅ, ๐‘ฆ)/12]

ind the following indefinite integral:โˆซ((โˆ’6๐‘ฅโˆ’3)๐‘ฅ5)d๐‘ฅ

For the Joint PMF as shown, find each of following quantities:๐‘๐‘‹ ๐‘ฅ , ๐‘๐‘Œ ๐‘ฆ , ๐‘๐‘‹|๐‘Œ ๐‘ฅ ๐‘ฆ , ๐‘๐‘Œ|๐‘‹ ๐‘ฆ ๐‘ฅ , ๐ธ[๐‘‹|๐‘Œ = 3]Also find whether ๐‘‹ and ๐‘Œ are independent or not.[The graph shows ๐‘๐‘‹,๐‘Œ(๐‘ฅ, ๐‘ฆ)/12

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.