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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an left parenthesis, x, comma, y, right parenthesis(x,y) point.y, equals, 2, x, squared, minus, 6y=2x 2 −6

Question

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an left parenthesis, x, comma, y, right parenthesis(x,y) point.y, equals, 2, x, squared, minus, 6y=2x 2 −6

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Solution

Para encontrar las coordenadas del vértice de la parábola dada, primero debemos reescribir la ecuación en la forma estándar de una parábola. La ecuación dada es:

y=2x26 y = 2x^2 - 6

La forma estándar de una parábola es:

y=ax2+bx+c y = ax^2 + bx + c

En este caso, a=2 a = 2 , b=0 b = 0 , y c=6 c = -6 .

El vértice de una parábola en la forma y=ax2+bx+c y = ax^2 + bx + c se encuentra usando la fórmula:

x=b2a x = -\frac{b}{2a}

Sustituyendo los valores de a a y b b :

x=022=0 x = -\frac{0}{2 \cdot 2} = 0

Ahora, para encontrar la coordenada y y del vértice, sustituimos x=0 x = 0 en la ecuación original:

y=2(0)26=6 y = 2(0)^2 - 6 = -6

Por lo tanto, las coordenadas del vértice son:

(0,6) (0, -6)

This problem has been solved

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