Thirteen times the thirteenth term of an arithmetic progressions equal to seven times the seventh term of the arithmetic progression. What is the twentieth term?a.- 1b.- 3c.0d.4

To solve this problem, we need to use the formula for the nth term of an arithmetic progression, which is a + (n-1)d, where a is the first term and d is the common difference.

Given that 13 times the 13th term equals 7 times the 7th term, we can write the equation as follows:

13[a + 12d] = 7[a + 6d]

Solving this equation gives us the common difference, d:

13a + 156d = 7a + 42d 6a = 114d d = 6a/114 = a/19

Now, we need to find the 20th term using the formula a + (n-1)d. Substituting n = 20 and d = a/19, we get:

20th term = a + 19(a/19) = 2a

Without knowing the value of the first term a, we cannot determine the exact value of the 20th term. Therefore, the problem as stated does not provide enough information to find a unique solution.