The ionization energy in Group I-A (alkali metals) decreases down the group. This is because as we move down the group, the atomic size increases due to the addition of new energy levels (shells). As a result, the outermost electron (which is the one to be removed during ionization) is further from the nucleus and is less attracted to the positive charge of the nucleus. Therefore, less energy is required to remove this electron, leading to a decrease in ionization energy.

So, the correct order of ionization energy in Group I-A is Li Na K Cs.

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The ionization energy in Group I-A (alkali metals) decreases down the group. This is because as we move down the group, the atomic size increases due to the addition of new energy levels (shells). As a result, the outermost electron (which is the one to be removed during ionization) is further from the nucleus and is less attracted to the positive charge of the nucleus. Therefore, less energy is required to remove this electron, leading to a decrease in ionization energy.

So, the correct order of ionization energy in Group I-A is Li > Na > K > Cs.

Knowee AI · Accepted Answer

The ionization energy in Group I-A (alkali metals) decreases down the group. This is because as we move down the group, the atomic size increases due to the addition of new energy levels (shells). As a result, the outermost electron (which is the one to be removed during ionization) is further from the nucleus and is less attracted to the positive charge of the nucleus. Therefore, less energy is required to remove this electron, leading to a decrease in ionization energy.

So, the correct order of ionization energy in Group I-A is Li > Na > K > Cs.

Ionisation energy in group I-A varies in the decreasing order asLi>Na>K>CSNa>Li>K>CSLi>CS>K>NaK>CS>Na>Li

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