Let f(x) be a differentiable function in the interval (0,2), then the value of ∫20f(x)dx
Question
Let f(x) be a differentiable function in the interval (0,2), then the value of ∫20f(x)dx
Solution
The question seems to be incomplete. The integral ∫20f(x)dx is missing the limits of integration. If you want to integrate from 0 to 2, it should be written as ∫ from 0 to 2 of 20f(x)dx.
Assuming that's what you meant, here's how you would solve it:
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First, note that the constant 20 can be factored out of the integral, so ∫ from 0 to 2 of 20f(x)dx = 20 * ∫ from 0 to 2 of f(x)dx.
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To evaluate the integral ∫ from 0 to 2 of f(x)dx, you would need to know the antiderivative F(x) of f(x), such that F'(x) = f(x).
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Once you have F(x), you can use the Fundamental Theorem of Calculus, which states that ∫ from a to b of f(x)dx = F(b) - F(a).
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So, ∫ from 0 to 2 of f(x)dx = F(2) - F(0).
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Therefore, ∫ from 0 to 2 of 20f(x)dx = 20 * (F(2) - F(0)).
Without knowing the specific function f(x), this is as far as we can go.
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