The question seems to be incomplete. However, I'll try to answer based on the information provided.

1. ROM selection will be of 5 lines: This statement is not necessarily true. The number of lines for ROM selection depends on the size of the ROM. In this case, the size of the ROM is not specified.

2. Decoder for RAM requires 2 inputs: This statement is true. The size of the RAM is 128x8, which means it has 128 locations each of 8 bits. To select one of these 128 locations, a binary number of 7 bits is needed (since 2^7 = 128). Therefore, the decoder for the RAM requires 7 inputs, not 2.

3. If ROM and RAM are attached, RAM requires more data lines: This statement is not necessarily true. The number of data lines required by the RAM and ROM depends on their sizes. In this case, the size of the ROM is not specified, so it's not possible to determine whether the RAM requires more data lines.

4. If ROM of 512x9 is attached in this system, at least certain lines will be similar: This statement is true. The ROM and RAM will share the same address lines and data lines. The size of the ROM is 512x9, which means it has 512 locations each of 9 bits. To select one of these 512 locations, a binary number of 9 bits is needed (since 2^9 = 512). Therefore, the ROM and RAM will have at least 9 similar lines.

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The question seems to be incomplete. However, I'll try to answer based on the information provided.

1. ROM selection will be of 5 lines: This statement is not necessarily true. The number of lines for ROM selection depends on the size of the ROM. In this case, the size of the ROM is not specified.

2. Decoder for RAM requires 2 inputs: This statement is true. The size of the RAM is 128x8, which means it has 128 locations each of 8 bits. To select one of these 128 locations, a binary number of 7 bits is needed (since 2^7 = 128). Therefore, the decoder for the RAM requires 7 inputs, not 2.

3. If ROM and RAM are attached, RAM requires more data lines: This statement is not necessarily true. The number of data lines required by the RAM and ROM depends on their sizes. In this case, the size of the ROM is not specified, so it's not possible to determine whether the RAM requires more data lines.

4. If ROM of 512x9 is attached in this system, at least certain lines will be similar: This statement is true. The ROM and RAM will share the same address lines and data lines. The size of the ROM is 512x9, which means it has 512 locations each of 9 bits. To select one of these 512 locations, a binary number of 9 bits is needed (since 2^9 = 512). Therefore, the ROM and RAM will have at least 9 similar lines.

Knowee AI · Accepted Answer

The question seems to be incomplete. However, I'll try to answer based on the information provided.

1. ROM selection will be of 5 lines: This statement is not necessarily true. The number of lines for ROM selection depends on the size of the ROM. In this case, the size of the ROM is not specified.

2. Decoder for RAM requires 2 inputs: This statement is true. The size of the RAM is 128x8, which means it has 128 locations each of 8 bits. To select one of these 128 locations, a binary number of 7 bits is needed (since 2^7 = 128). Therefore, the decoder for the RAM requires 7 inputs, not 2.

3. If ROM and RAM are attached, RAM requires more data lines: This statement is not necessarily true. The number of data lines required by the RAM and ROM depends on their sizes. In this case, the size of the ROM is not specified, so it's not possible to determine whether the RAM requires more data lines.

4. If ROM of 512x9 is attached in this system, at least certain lines will be similar: This statement is true. The ROM and RAM will share the same address lines and data lines. The size of the ROM is 512x9, which means it has 512 locations each of 9 bits. To select one of these 512 locations, a binary number of 9 bits is needed (since 2^9 = 512). Therefore, the ROM and RAM will have at least 9 similar lines.

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