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PQRS is a trapezium with PQ and RS parallel PQ = 6 cm, QR = 5 cm, RS = 3cm and PS = 4cm. The area of PQRS is

Question

PQRS is a trapezium with PQ and RS parallel PQ = 6 cm, QR = 5 cm, RS = 3cm and PS = 4cm. The area of PQRS is

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Solution

To find the area of a trapezium, we use the formula:

Area = 1/2 * (sum of parallel sides) * (distance between them)

In trapezium PQRS, PQ and RS are the parallel sides and PS is the distance between them.

Given, PQ = 6 cm, RS = 3 cm, and PS = 4 cm.

Substituting these values into the formula, we get:

Area = 1/2 * (6 cm + 3 cm) * 4 cm = 1/2 * 9 cm * 4 cm = 18 square cm

So, the area of the trapezium PQRS is 18 square cm.

This problem has been solved

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