Counting the Hours When men decided to divide the day into twenty-four hours, they used numbers one through twelve two times. As a result, there was one o’clock during the day and another one o’clock after midnight. This created confusion. If one was told to submit a project at six o’clock, did this mean six o’clock in the morning or at night? The Romans provided a solution to this problem. They thought that noon time, the time when the sun is at its apex, is an important time. They called noon Meridies and measured time by this. They called the morning ante meridiem, which means “before noon” while “after noon” was called post meridiem. Ante meridiem was shortened to A.M. while post meridiem was shortened to P.M. 10. The Romans thought of a solution. This means that they provided _____________________. (Inferential) a. an answer to the problem b. a better interpretation c. a new set of numbers d. another clock

The time shown is in the 24-hour clock.Express the time in the 12-hour clock.23 42 → .  p.m.

Here on earth, our 24-hour day is composed of two parts, each of 12 hours. Each hour in each part has a corresponding hour in the other part separated by 12 hours: the hour essentially measures the duration since the start of the daypart. For example, 1 hour in the first part of the day is equivalent to 13, which is 1 hour into the second part of the day.Now, consider the equivalent hours that are both prime numbers. We have 3 such instances for a 24-hour 2-part day:5~177~1911~23Accept two natural numbers D, P >1 corresponding respectively to a number of hours per day and the number of parts in a day separated by a space. D should be divisible by P, meaning that the number of hours per part (D/P) should be a natural number. Calculate the number of instances of equivalent prime hours. Output zero if there is no such instance. Note that we require each equivalent hour in each part in a day to be a prime number.Constraints:InputThe single line consists of two space-separated integers, D and P corresponding to the number of. hours per day and number of parts in a day respectivelyOutputOutput must be a single number, corresponding to the number of instances of equivalent prime number, as described aboveConstraints10 <= D < 5002 <= P < 50Example:Example 1:Input: 24 2Output: 3 Example 2:Input36 3Output2Explanation:In the given second example D = 36 and P = 3Duration of each day part = 122~14~X3~15~X5~17~29 – instance of equivalent prime hours7~19~31 – instance of equivalent prime hours11~23~XHence the answers is 2.

A clock seen through a mirror shows 8 o'clock.  What is the correct time?

Problem 1: Suppose you have a clock that only shows time in a 12-hour format. If it's currently 4:30 PM, what will be the time after 137 hours?*10 pointsAfter 137 hours, it will be 6 hours later on the clock. Therefore, the time will be 10:30 PM.After 137 hours, it will be 7 hours later on the clock. Therefore, the time will be 11:30 PM.After 137 hours, it will be 5 hours later on the clock. Therefore, the time will be 9:30 PM.After 137 hours, it will be 4 hours later on the clock. Therefore, the time will be 8:30 PM.

Problem 1: Suppose you have a clock that only shows time in a 12-hour format. If it's currently 4:30 PM, what will be the time after 137 hours?*10 pointsAfter 137 hours, it will be 6 hours later on the clock. Therefore, the time will be 10:30 PM.After 137 hours, it will be 7 hours later on the clock. Therefore, the time will be 11:30 PM.After 137 hours, it will be 5 hours later on the clock. Therefore, the time will be 9:30 PM.After 137 hours, it will be 4 hours later on the clock. Therefore, the time will be 8:30 PM.Problem 2: A group of friends decides to rotate the role of hosting a weekly game night. If they start at Alice's house this week and rotate every 4 weeks, where will the game night be 17 weeks from now?*10 pointsAfter 17 weeks, the game night will be at the house of the friend who is three position ahead in the rotation. If Alice starts, then it will be at the second person's house.After 17 weeks, the game night will be at the house of the friend who is two position ahead in the rotation. If Alice starts, then it will be at the second person's house.After 17 weeks, the game night will be at the house of the friend who is one position ahead in the rotation. If Alice starts, then it will be at the second person's house.After 17 weeks, the game night will be at the house of the friend who is of no position ahead in the rotation. If Alice starts, then it will be at the second person's house.