A 0.3 uC of source charge is placed in the electric field. Calculate it’s electric potential at a distance 5 cm away from a test charge.Group of answer choices54x10^-3 J/C54000 J10.8x10^7 J54x10^3 J/C
Question
A 0.3 uC of source charge is placed in the electric field. Calculate it’s electric potential at a distance 5 cm away from a test charge.Group of answer choices54x10^-3 J/C54000 J10.8x10^7 J54x10^3 J/C
Solution
The electric potential (V) at a point in an electric field is given by the equation:
V = kQ/r
where:
- k is Coulomb's constant (8.99 x 10^9 N.m^2/C^2),
- Q is the source charge (in Coulombs), and
- r is the distance from the source charge (in meters).
Given:
- Q = 0.3 uC = 0.3 x 10^-6 C (since 1 uC = 10^-6 C), and
- r = 5 cm = 0.05 m (since 1 cm = 0.01 m),
we can substitute these values into the equation to find V:
V = (8.99 x 10^9 N.m^2/C^2) * (0.3 x 10^-6 C) / 0.05 m V = 53.94 x 10^3 N.m/C V = 53.94 x 10^3 J/C (since 1 N.m = 1 J)
So, the electric potential at a distance 5 cm away from the 0.3 uC source charge is approximately 54 x 10^3 J/C.
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