If a car is traveling forward at 15 m/s, how fast will it be going in 1.2 seconds if the acceleration is -10 m/s^2?

Sure, here's how you can solve this problem:

Step 1: Understand the problem The car is moving forward at an initial speed (u) of 15 m/s. It is decelerating (negative acceleration) at a rate (a) of -10 m/s^2. We need to find the final speed (v) after a time (t) of 1.2 seconds.

Step 2: Use the formula for acceleration Acceleration is defined as the change in velocity per unit time. The formula for acceleration is:

a = (v - u) / t

We can rearrange this formula to solve for the final velocity (v):

v = u + a*t

Step 3: Substitute the given values into the formula Substitute u = 15 m/s, a = -10 m/s^2, and t = 1.2 s into the formula:

v = 15 m/s + (-10 m/s^2 * 1.2 s)

Step 4: Calculate the final speed v = 15 m/s - 12 m/s = 3 m/s

So, if a car is traveling forward at 15 m/s, it will be going at 3 m/s in 1.2 seconds if the acceleration is -10 m/s^2.