3 grams of a particular triglyceride (MW: 500 g/mol) are completely saponified under basic conditions to break all ester bonds, and the products of this reaction are then extracted with dilute aqueous acid. The fatty acid products are then dried and quantified via titration. What volume of 1M titrant is needed to reach the equivalence point?A.2 mL HClB.6 mL NaOHC.18 mL HClD.18 mL NaOH
Question
3 grams of a particular triglyceride (MW: 500 g/mol) are completely saponified under basic conditions to break all ester bonds, and the products of this reaction are then extracted with dilute aqueous acid. The fatty acid products are then dried and quantified via titration. What volume of 1M titrant is needed to reach the equivalence point?A.2 mL HClB.6 mL NaOHC.18 mL HClD.18 mL NaOH
Solution
To answer this question, we first need to understand the process of saponification. In saponification, a triglyceride reacts with a base to form glycerol and fatty acids. The molecular weight (MW) of the triglyceride is given as 500 g/mol.
Given that we have 3 grams of the triglyceride, we can calculate the number of moles of the triglyceride as follows:
Number of moles = mass / molecular weight = 3 g / 500 g/mol = 0.006 mol
In the saponification reaction, each mole of triglyceride produces three moles of fatty acid because a triglyceride has three ester bonds. Therefore, the number of moles of fatty acid produced is:
Number of moles of fatty acid = 3 * number of moles of triglyceride = 3 * 0.006 mol = 0.018 mol
In the titration process, each mole of fatty acid will react with one mole of the titrant to reach the equivalence point. Therefore, the volume of 1M titrant needed is equal to the number of moles of fatty acid, which is 0.018 mol.
Since 1M means there is 1 mole of the titrant in 1 liter (or 1000 mL) of solution, the volume of the titrant needed in mL is:
Volume of titrant = number of moles of fatty acid * 1000 mL = 0.018 mol * 1000 mL = 18 mL
Therefore, the correct answer is:
D. 18 mL NaOH
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