Of two numbers, 1/5th of a the greater equal to 1/3rd of the smaller and their sum is 16. Find the numbers.a.7, 5b.9, 7c.11, 5d.10, 6
Question
Of two numbers, 1/5th of a the greater equal to 1/3rd of the smaller and their sum is 16. Find the numbers.a.7, 5b.9, 7c.11, 5d.10, 6
Solution
Let's denote the two numbers as x and y, where x is the greater number and y is the smaller number.
From the problem, we have two equations:
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1/5 * x = 1/3 * y (This is because 1/5th of the greater number is equal to 1/3rd of the smaller number)
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x + y = 16 (This is because the sum of the two numbers is 16)
We can solve these two equations simultaneously to find the values of x and y.
First, let's express y in terms of x using the first equation:
y = 3/5 * x
Now, let's substitute y in the second equation:
x + 3/5 * x = 16
This simplifies to:
8/5 * x = 16
Solving for x gives:
x = 16 * 5/8 = 10
Substituting x = 10 in the equation y = 3/5 * x gives:
y = 3/5 * 10 = 6
So, the two numbers are 10 and 6, which corresponds to option d.
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