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16 A technical article about diesel engines expresses the energy available from diesel fuel both as41.8 MJ kg –1 and as 34.9 GJ m–3.What is the density of diesel fuel?A 8.35  10 2 kg m–3B 1.20  10 3 kg m–3C 8.35  10 5 kg m–3D 1.20  10 6 kg m–317 What is meant by the efficiency of a system?A the difference between the useful energy output from the system and the total energy inputB the difference between the useful energy output from the system and the wasted energyoutputC the ratio of the useful energy output from the system to the total energy inputD the ratio of the useful energy output from the system to the wasted energy output

Question

16 A technical article about diesel engines expresses the energy available from diesel fuel both as41.8 MJ kg –1 and as 34.9 GJ m–3.What is the density of diesel fuel?A 8.35  10 2 kg m–3B 1.20  10 3 kg m–3C 8.35  10 5 kg m–3D 1.20  10 6 kg m–317 What is meant by the efficiency of a system?A the difference between the useful energy output from the system and the total energy inputB the difference between the useful energy output from the system and the wasted energyoutputC the ratio of the useful energy output from the system to the total energy inputD the ratio of the useful energy output from the system to the wasted energy output

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Solution

  1. The density of a substance can be calculated by dividing its energy per volume by its energy per mass. In this case, the energy per volume of diesel fuel is given as 34.9 GJ/m^3 and the energy per mass is given as 41.8 MJ/kg.

First, we need to convert GJ/m^3 to MJ/m^3. 1 GJ = 1000 MJ, so 34.9 GJ/m^3 = 34900 MJ/m^3.

Then, we divide the energy per volume by the energy per mass:

34900 MJ/m^3 ÷ 41.8 MJ/kg = 835.4 kg/m^3

So, the density of diesel fuel is approximately 835 kg/m^3, which is closest to option A: 8.35 x 10^2 kg/m^3.

  1. The efficiency of a system is defined as the ratio of the useful energy output from the system to the total energy input. This is because efficiency measures how effectively a system converts input energy into useful output energy. Therefore, the correct answer is option C.

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