Arrange these action potential events in their proper sequence: (1) The neuron is stimulated at the dendrites (2) K+ gates open (3) The neuron is in a polarized “resting” state (4) Na+ gates open (5) The cell is fully depolarized (6) The cell is fully repolarized a. 1, 2, 4, 3, 5, 6b. 3, 1, 4, 5, 2, 6c. 4, 6, 2, 1, 5, 3d. 1, 4, 2, 6, 5, 3
Question
Arrange these action potential events in their proper sequence: (1) The neuron is stimulated at the dendrites (2) K+ gates open (3) The neuron is in a polarized “resting” state (4) Na+ gates open (5) The cell is fully depolarized (6) The cell is fully repolarized a. 1, 2, 4, 3, 5, 6b. 3, 1, 4, 5, 2, 6c. 4, 6, 2, 1, 5, 3d. 1, 4, 2, 6, 5, 3
Solution
The correct sequence for these action potential events is option b. 3, 1, 4, 5, 2, 6.
Here's the step-by-step explanation:
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The neuron is in a polarized “resting” state: This is the starting point, where the inside of the neuron is negatively charged compared to the outside.
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The neuron is stimulated at the dendrites: A stimulus causes a change in the neuron's membrane potential.
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Na+ gates open: If the stimulus is strong enough, it triggers the opening of sodium channels, allowing Na+ ions to rush into the cell.
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The cell is fully depolarized: The influx of Na+ ions makes the inside of the neuron positively charged, causing depolarization.
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K+ gates open: After the cell is depolarized, potassium channels open, allowing K+ ions to flow out of the cell.
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The cell is fully repolarized: The outflow of K+ ions returns the cell to its negative internal charge, repolarizing it.
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