At which values of x does the function F(x) have a vertical asymptote? Check all that apply.𝐹(𝑥)=1(𝑥−4)(𝑥+1)F(x)= (x−4)(x+1)1 A.0B.-4C.-1D.2E.4F.1SUBMITarrow_backPREVIOUS
Question
At which values of x does the function F(x) have a vertical asymptote? Check all that apply.𝐹(𝑥)=1(𝑥−4)(𝑥+1)F(x)= (x−4)(x+1)1 A.0B.-4C.-1D.2E.4F.1SUBMITarrow_backPREVIOUS
Solution
The function F(x) = 1/(x-4)(x+1) has vertical asymptotes where the denominator equals zero, because division by zero is undefined in mathematics.
To find these points, we set the denominator equal to zero and solve for x:
x - 4 = 0 => x = 4
x + 1 = 0 => x = -1
So, the function F(x) has vertical asymptotes at x = 4 and x = -1.
Therefore, the correct answers are E. 4 and C. -1.
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