You need to prepare 0.500 L of a solution of potassium sulfate.The required molar concentration (molarity) is 0.127 mol L-1 potassium sulfate.Calculate the mass of potassium sulfate in grams required for this solution.Enter your answer with three significant figures, do not include units.
Question
You need to prepare 0.500 L of a solution of potassium sulfate.The required molar concentration (molarity) is 0.127 mol L-1 potassium sulfate.Calculate the mass of potassium sulfate in grams required for this solution.Enter your answer with three significant figures, do not include units.
Solution
To calculate the mass of potassium sulfate required, we first need to find out how many moles of potassium sulfate are needed.
Step 1: Calculate the number of moles needed Molarity (M) = moles of solute / volume of solution in liters So, moles of solute = Molarity * volume of solution = 0.127 mol/L * 0.500 L = 0.0635 mol
Step 2: Convert moles to grams We know that the molar mass of potassium sulfate (K2SO4) is approximately 174.26 g/mol. So, mass = moles * molar mass = 0.0635 mol * 174.26 g/mol = 11.1 g
Therefore, you need 11.1 grams of potassium sulfate to prepare 0.500 L of a 0.127 M solution.
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