To find the resulting concentration of the solution, we can use the formula for dilution: M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

1. First, we need to convert the volumes to the same units. In this case, both are already in liters, so no conversion is necessary.

2. Next, we plug the given values into the formula:

(2 M)(1 L) = M2(1.78 L)

3. To solve for M2, we divide both sides of the equation by 1.78 L:

M2 = (2 M * 1 L) / 1.78 L

4. Performing the calculation gives us the final molarity (M2) of the solution:

M2 = 1.12 M

So, the resulting concentration of the LiNO3 solution after dilution is 1.12 M.

Question

To find the resulting concentration of the solution, we can use the formula for dilution: M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

1. First, we need to convert the volumes to the same units. In this case, both are already in liters, so no conversion is necessary.

2. Next, we plug the given values into the formula:

(2 M)(1 L) = M2(1.78 L)

3. To solve for M2, we divide both sides of the equation by 1.78 L:

M2 = (2 M * 1 L) / 1.78 L

4. Performing the calculation gives us the final molarity (M2) of the solution:

M2 = 1.12 M

So, the resulting concentration of the LiNO3 solution after dilution is 1.12 M.

Knowee AI · Accepted Answer

To find the resulting concentration of the solution, we can use the formula for dilution: M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

1. First, we need to convert the volumes to the same units. In this case, both are already in liters, so no conversion is necessary.

2. Next, we plug the given values into the formula:

(2 M)(1 L) = M2(1.78 L)

3. To solve for M2, we divide both sides of the equation by 1.78 L:

M2 = (2 M * 1 L) / 1.78 L

4. Performing the calculation gives us the final molarity (M2) of the solution:

M2 = 1.12 M

So, the resulting concentration of the LiNO3 solution after dilution is 1.12 M.

A solution of LiNO3 at 2 M is diluted from a volume of 1 L to its new volume of 1.78 L. What is the resulting concentration of this solution?

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