BackgroundThe electric field 𝐸→ of a particle with charge 𝑞 can be derived from its electric potential 𝑉:𝐸→=−∇𝑉where ∇ is the derivative operator and 𝑉 at every point in space is 𝑉=14𝜋𝜀0𝑞||𝑟→||where 𝑟→ is the distance from the particle at that point, 14𝜋𝜀0 is some constant, and ||𝑟→||=𝑟𝑥2+𝑟𝑦2 (in a two-dimensional plane). The net electric potential at any point is the sum of all of the electric potentials from all the particles.The force from particle 𝐵 on particle 𝐴 is the charge of 𝐴 (𝑞𝐴) multiplied by the electric field from 𝐵: 𝐹→𝐵→𝐴=𝑞𝐴𝐸→𝐵=14𝜋𝜀0𝑞𝐴⋅𝑞𝐵||𝑟→||2𝑟^For this problem, however, you will only visualize the electric potential 𝑉.ProblemGiven two kinds of particles, those with a positive charge +𝑒, and those with negative charges −𝑒, display the electric potential at every point in space. The electric potential should be normalized relative to |𝑒|4𝜋𝜀0 (i.e., treat |𝑒|4𝜋𝜀0 as 1).InputInput starts with 3 integers 𝑛,𝑚,𝑞 where 0<𝑛,𝑚≤50 and 0<𝑞≤10. Then follows 𝑞 lines: each line contains three values 𝑥,𝑦,𝑠, where 1≤𝑥≤𝑚 and 1≤𝑦≤𝑛 correspond to the integer coordinates of the charged particle and 𝑠 is the sign of the particle’s charge being either a + or a -. No two particles will have the same coordinates.OutputYour output should be an 𝑛×𝑚 grid of ASCII characters oriented with the positive 𝑦-axis pointing down and the positive 𝑥-axis pointing to the right, with coordinates starting from 1. Every character in the grid corresponds to the total potential at that point.If the field contains a particle, print either a + or - corresponding to its charge. Otherwise, the character you place will be related to the sign of the potential. If the potential is negative then use the characters {%,X,x}. If it is positive, however, use the character set {0,O,o} (the first element is a zero).There are 3 tiers to the field’s magnitude:1/𝜋1/𝜋21/𝜋3If the field is below the third tier print a “.”.If the magnitude is above the first tier then you would use % or 0 (zero) depending on the sign, if it is below the first tier then you would use X or O, and so on and so forth.Sample Input 1 Sample Output 120 20 25 5 +15 15 -OOOOOOOOOoooo.......OOOOOOOOOoooo.......OOO000OOOOooo.......OO00000OOOooo.......OO00+00OOOoo........OO00000OOooo........OOO000OOOoo....xxxxxOOOOOOOOoo...xxxxxxxOOOOOOOoo...xxxxxxxxooOOOooo...xxxXXXxxxooooooo...xxXXXXXXXxoooooo...xxXXXXXXXXXoooo....xxXXX%%%XXXX.......xxxXX%%%%%XXX.......xxXXX%%-%%XXX......xxxXXX%%%%%XXX......xxxXXXX%%%XXXX......xxxxXXXXXXXXXX......xxxxXXXXXXXXXX......xxxxxXXXXXXXXxSample Input 2 Sample Output 220 20 315 15 -10 10 +5 5 -XXXXXXXXXXxxxxxxxxxxXXXXXXXXXXxxxxxxxxxxXXX%%%XXXXxxxxxxxxxxXX%%%%%XXXxxxxxxxxxxXX%%-%%XXxxxxxxxxxxxXX%%%%%Xxx..xxxxxxxxXXX%%%Xx.oo..xxxxxxxXXXXXXx.OOOo..xxxxxxXXXXXx.O000Oo.xxxxxxXXXXxxoO0+0OoxxXXXXXxxxxx.oO000O.xXXXXXXxxxxx..oOOO.xXXXXXXXxxxxxx..oo.xX%%%XXXXxxxxxxx..xxX%%%%%XXXxxxxxxxxxxXX%%-%%XXXxxxxxxxxxXXX%%%%%XXXxxxxxxxxxXXXX%%%XXXXxxxxxxxxxXXXXXXXXXXXxxxxxxxxxXXXXXXXXXXXxxxxxxxxxXXXXXXXXXXXSample Input 3 Sample Output 320 20 210 2 +10 18 -oooOOOO00000OOOOoooooooOOOO00+00OOOOoooooooOOOO00000OOOOooooooooOOOO000OOOOooooooooooOOOOOOOOOooooooooooooOOOOOOOoooooo..oooooooOOOooooooo......ooooooooooo.....................................................................xxxxxxxxxxx......xxxxxxxXXXxxxxxxx..xxxxxxXXXXXXXxxxxxx.xxxxxXXXXXXXXXxxxxxxxxxxXXXX%%%XXXXxxxxxxxxXXXX%%%%%XXXXxxxxxxxXXXX%%-%%XXXXxxxxxxxXXXX%%%%%XXXXxxxxxxxXXXXX%%%XXXXXxxxx