In the monostable multivibrator, the frequency of the input triggered signal is 5 KHz with 75% duty cycle. If the value of C is 0.01 micro-Farads, what is the value of external resistance (in K Ohms)?

The monostable multivibrator is a one-shot timer. It is triggered by an input signal, and then it produces an output pulse of a certain duration, which is determined by the RC time constant of an external resistor and capacitor.

The frequency of the input triggered signal is 5 KHz, which means the period of the signal is 1/5000 = 0.0002 seconds or 200 microseconds.

The duty cycle is the percentage of one period in which a signal is active. A duty cycle of 75% means that the signal is active for 75% of the period. So, the duration of the output pulse is 75% of 200 microseconds, which is 150 microseconds.

The duration of the output pulse is also equal to the RC time constant, which is the product of the resistance (R) and the capacitance (C). Given that the capacitance C is 0.01 microfarads, we can set up the equation:

RC = 150 microseconds R = 150 microseconds / 0.01 microfarads = 15000 ohms or 15 K ohms.

So, the value of the external resistance should be 15 K ohms.