Sure! Here is a step-by-step guide to create and display a single linked list in C:

Step 1: Define the structure for a node in the linked list. Each node should contain a data element and a pointer to the next node.

```c
struct Node {
int data;
struct Node* next;
};
```

Step 2: Create a function to insert a new node at the beginning of the linked list. This function will take the data value as a parameter and return the updated head of the linked list.

```c
struct Node* insertNode(struct Node* head, int data) {
struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
newNode-data = data;
newNode-next = head;
head = newNode;
return head;
}
```

Step 3: Create a function to display the linked list. This function will traverse the linked list and print the data value of each node.

```c
void displayList(struct Node* head) {
struct Node* current = head;
while (current != NULL) {
printf("%d ", current-data);
current = current-next;
}
printf("
");
}
```

Step 4: In the main function, create the head pointer and insert nodes into the linked list using the `insertNode` function. Finally, display the linked list using the `displayList` function.

```c
int main() {
struct Node* head = NULL;

// Insert nodes into the linked list
head = insertNode(head, 5);
head = insertNode(head, 10);
head = insertNode(head, 15);

// Display the linked list
displayList(head);

return 0;
}
```

This program will create a single linked list with three nodes containing the data values 15, 10, and 5. It will then display the linked list in reverse order, i.e., 5 10 15.

Question

Sure! Here is a step-by-step guide to create and display a single linked list in C:

Step 1: Define the structure for a node in the linked list. Each node should contain a data element and a pointer to the next node.

```c
struct Node {
    int data;
    struct Node* next;
};
```

Step 2: Create a function to insert a new node at the beginning of the linked list. This function will take the data value as a parameter and return the updated head of the linked list.

```c
struct Node* insertNode(struct Node* head, int data) {
    struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
    newNode->data = data;
    newNode->next = head;
    head = newNode;
    return head;
}
```

Step 3: Create a function to display the linked list. This function will traverse the linked list and print the data value of each node.

```c
void displayList(struct Node* head) {
    struct Node* current = head;
    while (current != NULL) {
        printf("%d ", current->data);
        current = current->next;
    }
    printf("
");
}
```

Step 4: In the main function, create the head pointer and insert nodes into the linked list using the `insertNode` function. Finally, display the linked list using the `displayList` function.

```c
int main() {
    struct Node* head = NULL;
    
    // Insert nodes into the linked list
    head = insertNode(head, 5);
    head = insertNode(head, 10);
    head = insertNode(head, 15);
    
    // Display the linked list
    displayList(head);
    
    return 0;
}
```

This program will create a single linked list with three nodes containing the data values 15, 10, and 5. It will then display the linked list in reverse order, i.e., 5 10 15.

Knowee AI · Accepted Answer