There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student.You may perform the following move any number of times:Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1)Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.Note that there may be multiple seats or students in the same position at the beginning.
Question
There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student.You may perform the following move any number of times:Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1)Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.Note that there may be multiple seats or students in the same position at the beginning.
Solution
To solve this problem, you can follow these steps:
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First, sort both the 'seats' and 'students' arrays in ascending order. This is because the minimum number of moves can be achieved by pairing the student and the seat with the closest possible positions.
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Initialize a variable, say 'moves', to keep track of the total number of moves. Set it to 0 initially.
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Iterate over the arrays 'seats' and 'students' simultaneously. For each pair of seat and student, calculate the absolute difference between their positions and add it to 'moves'. This is because the number of moves required to move a student from one position to another is equal to the absolute difference between these positions.
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Finally, return 'moves' as the minimum number of moves required to move each student to a seat.
Here is a Python code snippet that implements the above steps:
def minMoves(seats, students):
seats.sort()
students.sort()
moves = 0
for i in range(len(seats)):
moves += abs(seats[i] - students[i])
return moves
This function takes as input two lists: 'seats' and 'students', representing the positions of the seats and the students respectively. It returns the minimum number of moves required to move each student to a seat such that no two students are in the same seat.
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