Which pair of coordinate points have the least distance between them?REASONING(-2, -11) and (-18, -41)(4, -8) and (19, -28)(-9, 14) and (9, -10)(17, 9) and (7, 33)
Question
Which pair of coordinate points have the least distance between them?REASONING(-2, -11) and (-18, -41)(4, -8) and (19, -28)(-9, 14) and (9, -10)(17, 9) and (7, 33)
Solution
To find the pair of coordinate points with the least distance between them, we can use the distance formula which is derived from the Pythagorean theorem. The distance between two points (x1, y1) and (x2, y2) is given by:
d = sqrt[(x2-x1)² + (y2-y1)²]
Let's calculate the distance for each pair:
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For (-2, -11) and (-18, -41): d = sqrt[(-18 - (-2))² + (-41 - (-11))²] d = sqrt[(-16)² + (-30)²] d = sqrt[256 + 900] d = sqrt[1156] d = 34
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For (4, -8) and (19, -28): d = sqrt[(19 - 4)² + (-28 - (-8))²] d = sqrt[15² + (-20)²] d = sqrt[225 + 400] d = sqrt[625] d = 25
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For (-9, 14) and (9, -10): d = sqrt[(9 - (-9))² + (-10 - 14)²] d = sqrt[18² + (-24)²] d = sqrt[324 + 576] d = sqrt[900] d = 30
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For (17, 9) and (7, 33): d = sqrt[(7 - 17)² + (33 - 9)²] d = sqrt[(-10)² + 24²] d = sqrt[100 + 576] d = sqrt[676] d = 26
So, the pair of coordinate points with the least distance between them is (4, -8) and (19, -28) with a distance of 25 units.
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