Which phase of meiotic division results in the formation of four daughter cells with the haploid number of chromosomes?a.first b.thirdc.second
Question
Which phase of meiotic division results in the formation of four daughter cells with the haploid number of chromosomes?a.first b.thirdc.second
Solution
The phase of meiotic division that results in the formation of four daughter cells with the haploid number of chromosomes is the second phase, so the answer is c. second.
Here's a step-by-step explanation:
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Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. This process is required to produce egg and sperm cells for sexual reproduction.
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Meiosis consists of two divisions, both of which follow the same stages as mitosis (prophase, metaphase, anaphase, telophase).
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The first meiotic division (Meiosis I) is a reductional division, i.e., the number of chromosomes is reduced from diploid to haploid. At the end of Meiosis I, there are two daughter cells with half the number of chromosomes.
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The second meiotic division (Meiosis II) is an equational division, i.e., similar to mitosis, where the number of chromosomes remains the same. At the end of Meiosis II, there are four daughter cells, each with a haploid number of chromosomes.
So, the phase of meiotic division that results in the formation of four daughter cells with the haploid number of chromosomes is the second phase.
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